College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 43



Work Step by Step

We use the quadratic formula: $10y^{2}-16y+5=0$ $x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}=\frac{-(-16)\pm\sqrt{(-16)^{2}-4(10)(5)}}{2(10)}=\frac{16\pm\sqrt{256-200}}{20}=\frac{16\pm\sqrt{56}}{20}=\frac{16\pm\sqrt{4*14}}{20}=\frac{16\pm2\sqrt{14}}{20}=\frac{8\pm\sqrt{14}}{10}$
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