#### Answer

$x=0.9$

#### Work Step by Step

We use the quadratic formula:
$x^{2}-1.800x+0.810=0$
$x=\displaystyle \frac{-(-1.8)\pm\sqrt{(-1.8)^{2}-4(1)(0.81)}}{2(1)}=\frac{1.8\pm\sqrt{3.24-3.24}}{2}=\frac{1.8\pm\sqrt{0}}{2}=\frac{1.8}{2}=0.9$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=0.9$

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