College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 32


$x=-\frac{7}{5}$ or $x=\frac{1}{2}$

Work Step by Step

We solve by factoring: $10x^{2}+9x-7=0$ $(5x+7)(2x-1)=0$ $x=-\frac{7}{5}$ or $x=\frac{1}{2}$
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