#### Answer

$x=-\frac{7}{5}$ or $x=\frac{1}{2}$

#### Work Step by Step

We solve by factoring:
$10x^{2}+9x-7=0$
$(5x+7)(2x-1)=0$
$x=-\frac{7}{5}$ or $x=\frac{1}{2}$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=-\frac{7}{5}$ or $x=\frac{1}{2}$

We solve by factoring:
$10x^{2}+9x-7=0$
$(5x+7)(2x-1)=0$
$x=-\frac{7}{5}$ or $x=\frac{1}{2}$

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