Answer
$y=-\displaystyle \frac{7}{4}$ or $y=4$
Work Step by Step
We solve by factoring:
$4y^{2}-9y=28$
$4y^{2}-9y-28=0$
$(4y+7)(y-4)=0$
$4y+7=0$ or $y-4=0$
So we have: $y=-\displaystyle \frac{7}{4}$ or $y=4$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 12
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