College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 12


$y=-\displaystyle \frac{7}{4}$ or $y=4$

Work Step by Step

We solve by factoring: $4y^{2}-9y=28$ $4y^{2}-9y-28=0$ $(4y+7)(y-4)=0$ $4y+7=0$ or $y-4=0$ So we have: $y=-\displaystyle \frac{7}{4}$ or $y=4$
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