## College Algebra 7th Edition

Published by Brooks Cole

# Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 58

#### Answer

One real solution.

#### Work Step by Step

We find the discriminant: $x^{2}=6x-9$ $x^{2}-6x+9=0$ $D=b^{2}-4ac=(-6)^{2}-4(1)(9)=36-36=0$ The discriminant is 0, so there is one real solution.

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