## College Algebra 7th Edition

$x=\frac{2}{3}$
We solve by factoring. First we multiply through by 9: $x^{2}-\frac{4}{3}x+\frac{4}{9}=0$ Then we factor: $9x^{2}-12x+4=0$ $(3x-2)^{2}=0$ $x=\frac{2}{3}$