College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 37



Work Step by Step

We solve by factoring. First we multiply through by 9: $x^{2}-\frac{4}{3}x+\frac{4}{9}=0$ Then we factor: $9x^{2}-12x+4=0$ $(3x-2)^{2}=0$ $x=\frac{2}{3}$
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