## College Algebra 7th Edition

$z=-\displaystyle \frac{5}{6}$ or $z=\displaystyle \frac{9}{2}$
We solve by factoring: $12z^{2}-44z=45$ $12z^{2}-44z-45=0$ $(6z+5)(2z-9)=0$ $6z+5=0$ or $2z-9=0$ So we have: $z=-\displaystyle \frac{5}{6}$ or $z=\displaystyle \frac{9}{2}$