Answer
$x=4\pm\sqrt{15}$
Work Step by Step
We complete the square:
$x^{2}-8x+1=0$
$x^{2}-8x=-1$
$x^{2}-8x+16=-1+16$
$(x-4)^{2}=15$
$x-4=\pm\sqrt{15}$
$x=4\pm\sqrt{15}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 17
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