#### Answer

$x=4\pm\sqrt{15}$

#### Work Step by Step

We complete the square:
$x^{2}-8x+1=0$
$x^{2}-8x=-1$
$x^{2}-8x+16=-1+16$
$(x-4)^{2}=15$
$x-4=\pm\sqrt{15}$
$x=4\pm\sqrt{15}$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=4\pm\sqrt{15}$

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