College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.4 - Solving Quadratic Equations - 1.4 Exercises - Page 123: 17



Work Step by Step

We complete the square: $x^{2}-8x+1=0$ $x^{2}-8x=-1$ $x^{2}-8x+16=-1+16$ $(x-4)^{2}=15$ $x-4=\pm\sqrt{15}$ $x=4\pm\sqrt{15}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.