Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 73

Answer

(a) The graph is as shown. (b) The $x$-intercepts are $(-3,0)$ and $(1,0)$. (c) The solution is: $x=-3,1$ (d) The result in part (c) is the same with the $x$-intercepts of the graph.

Work Step by Step

(a) The graph is as shown. (b) The $x$-intercepts are $(-3,0)$ and $(1,0)$. (c) Setting $y=0$: $$0=|x+1|-2$$ $$|x+1|=2$$ Taking the positive: $$x+1=2$$ $$x=1$$ Taking the negative: $$x+1=-2$$ $$x=-3$$ Thus, the solution is: $$x=-3,1$$ (d) The result in part (c) is the same with the $x$-intercepts of the graph.
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