Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 60


Solutions: $x=\frac{5}{3}$ and $x=-3$

Work Step by Step

$|3x+2|=7$ 1) The value inside the bars is positive: $3x+2=7$ $3x=5$ $x=\frac{5}{3}$ 2) The value inside the bars is negative: $-(3x+2)=7$ $3x+2=-7$ $3x=-9$ $x=-3$ Testing: - $x=\frac{5}{3}$: $|3(\frac{5}{3})+2|=|5+2|=|7|=7$ - $x=-3$: $|3(-3)+2|=|-9+2|=|-7|=7$
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