-2, $+i\sqrt 3$, $-i\sqrt 3$
Work Step by Step
$x^3+2x^2+3x+6=0$ $(x+2)x^2+3(x+2)=0$ $(x^2+3)(x+2)=0$ Hence, x = -2 or $+i\sqrt 3$ or $-i\sqrt 3$
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