## Algebra and Trigonometry 10th Edition

-2, $+i\sqrt 3$, $-i\sqrt 3$
$x^3+2x^2+3x+6=0$ $(x+2)x^2+3(x+2)=0$ $(x^2+3)(x+2)=0$ Hence, x = -2 or $+i\sqrt 3$ or $-i\sqrt 3$