Answer
-2, $+i\sqrt 3$, $-i\sqrt 3$
Work Step by Step
$x^3+2x^2+3x+6=0$
$(x+2)x^2+3(x+2)=0$
$(x^2+3)(x+2)=0$
Hence, x = -2 or $+i\sqrt 3$ or $-i\sqrt 3$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 14
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