Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 29



Work Step by Step

Let a=$t^{\frac{1}{3}}$ $9a^2+24a+16=(3a+4)^2=0$ a = -4/3 $t^{\frac{1}{3}}=-4/3$ t=-64/27
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