Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 34



Work Step by Step

$\sqrt {3x+1}=7~~$ (Square both sides) $(\sqrt {3x+1})^2=7^2$ $3x+1=49$ $3x=48$ $x=\frac{48}{3}=16$ Check the solution; $\sqrt {3(16)+1}=\sqrt {48+1}=\sqrt {49}=7$
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