# Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 27

1/4

#### Work Step by Step

Let a = $\sqrt x$ Hence a>=0 $2a^2+9a=5$ $2a^2-a+10a-5=a(2a-1)+5(2a-1)=(a+5)(2a-1)=0$ Hence a=-5 or 1/2. Since a>=0, a=1/2 $\sqrt x=1/2$ x=1/4

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