Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 53


$\frac{-3+\sqrt {21}}{6}, \frac{-3-\sqrt {21}}{6}$

Work Step by Step

$1/x - 1/(x+1)=3$ $x+1 - x= 3x(x+1)$ $1 = 3x^2+3x$ $3x^2+3x-1=0$ Using the discriminant rule for quadratic equations to find the roots we get x= $\frac{-3+\sqrt {21}}{6}$ or $ \frac{-3-\sqrt {21}}{6}$
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