Algebra and Trigonometry 10th Edition

$4/(x+1)-3/(x+2)=1$ 4(x+2)-3(x+1)=(x+1)(x+2) $x+5 = x^2+3x+2$ $x^2+2x-3 = x^2+3x-x-3=x(x+3)-1(x+3)=0$ $(x+3)(x-1)=0$, giving x=-3 or 1