## Algebra and Trigonometry 10th Edition

$\frac{1+5\sqrt 5}{2}, \frac{1-5\sqrt 5}{2}$
$x^2-x-22=27^\frac{2}{3}=9$ $x^2-x-31=0$ Using the discriminant formula : x = $\frac{1+5\sqrt 5}{2}$ or $\frac{1-5\sqrt 5}{2}$