## Algebra and Trigonometry 10th Edition

$2\sqrt {x+1}=1+\sqrt {2x+3}$ $4(x+1) = 1+ 2x+3 +2\sqrt {2x+3}$ $2x = 2\sqrt {2x+3}$ $x^2=2x+3$ (x-3)(x+1) = 0 x=3 or -1 Check the solutions to check for extraneous solutions. x = -1 gives 0 = 2, contradiction x=3 gives 4=4 which is a valid solution