## Algebra and Trigonometry 10th Edition

$3x(x-1)^\frac{1}{2}+2(x-1)^\frac{3}{2}=0$ $\sqrt {x-1}(3x+2(x-1)) = \sqrt {x-1}(5x-2)=0$ x=1 or 2/5 Checking the solutions in the original equation x=2/5 is extraneous. (as x-1 should be >=0 for $\sqrt{x-1}$ to be defined)