## Algebra and Trigonometry 10th Edition

$x=-15$
$\sqrt[3] {12-x}-3=0$ $\sqrt[3] {12-x}=3~~$ (Cube both sides) $(\sqrt[3] {12-x})^3=3^3$ $12-x=27$ $-x=27-12=15$ $x=-15$ Check the solution: $\sqrt[3] {12-(-15)}-3=\sqrt[3] {12+15}-3=\sqrt[3] {27}-3=3-3=0$