Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 36



Work Step by Step

$\sqrt[3] {12-x}-3=0$ $\sqrt[3] {12-x}=3~~$ (Cube both sides) $(\sqrt[3] {12-x})^3=3^3$ $12-x=27$ $-x=27-12=15$ $x=-15$ Check the solution: $\sqrt[3] {12-(-15)}-3=\sqrt[3] {12+15}-3=\sqrt[3] {27}-3=3-3=0$
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