Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 28



Work Step by Step

Let a=$\sqrt x$, hence a>=0 $6a^2-7a-3=6a^2+2a-9a-3=2a(3a+1)-3(3a+1)=(2a-3)(3a+1)=0$ Either a = 3/2 or -1/3. Since a>=0, a=3/2 $\sqrt x=3/2$ x=9/4
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