Work Step by Step
Let a=$\sqrt x$, hence a>=0 $6a^2-7a-3=6a^2+2a-9a-3=2a(3a+1)-3(3a+1)=(2a-3)(3a+1)=0$ Either a = 3/2 or -1/3. Since a>=0, a=3/2 $\sqrt x=3/2$ x=9/4
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