Answer
9/4
Work Step by Step
Let a=$\sqrt x$, hence a>=0
$6a^2-7a-3=6a^2+2a-9a-3=2a(3a+1)-3(3a+1)=(2a-3)(3a+1)=0$
Either a = 3/2 or -1/3. Since a>=0, a=3/2
$\sqrt x=3/2$
x=9/4
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 28
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