Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.6 - Other Types of Equations - 1.6 Exercises - Page 128: 38

Answer

$x=\frac{3}{4}$

Work Step by Step

$2x=\sqrt {-5x+24} -3$ $2x+3=\sqrt {-5x+24}$ Squaring both sides of the equation.. $4x^2+12x+9=-5x+24$ $4x^2+17x-15=0$ $4x^2+20x-3x-15=0$ $4x(x+5)-3(x+5)=0$ $(4x-3)(x+5)=0$ $x=-5$ $x=\frac{3}{4}$ Check: For $x=\frac{3}{4}$ $\frac{3}{2}=\sqrt {\frac{81}{4}} -3, \frac{3}{2}=\frac{3}{2}\checkmark$ For $x=-5$ $-10=\sqrt {49}-3,-10=7-3,-10=4$ Thus, $x=-5$ is an extraneous solution to the equation. The solution of the given equation is $x=\frac{3}{4}$.
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