Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 80

Answer

$2y(2x-7y)(3x-y)$.

Work Step by Step

The given expression is $=12x^2y-46xy^2+14y^3$ Factor out $2y$. $=2y(6x^2-23xy+7y^2)$ Rewrite $-23xy$ as $-21xy-2xy$. $=2y(6x^2-21xy-2xy+7y^2)$ Group terms. $=2y[(6x^2-21xy)+(-2xy+7y^2)]$ Factor from each group. $=2y[3x(2x-7y)-y(2x-7y)]$ Factor out $(2x-7y)$. $=2y(3x-y)(2x-7y)$ Rearrange. $=2y(2x-7y)(3x-y)$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.