Answer
$(2y+1)(4y+3)$
Work Step by Step
$8y^{2}+10y+3=$
... Searching for two factors of $ac=+24$ whose sum is $b=+10,$
we find$\qquad+6$ and $+4.$
Rewrite the middle term and factor in pairs:
$=8y^{2}+4y+6y+3=$
$=4y(2y+1)+3(2y+1)$
= $(2y+1)(4y+3)$
