Answer
$4y(y+6)(y-3)$
Work Step by Step
All terms are divisible by $4y$, so factor out $4y$ to obtain:
$=4y(y^2+3y-18)$
Factor the trinomial. Look for factors of $-18$ whose sum is $3$. These factors are $6$ and $-3$.
This means that the trinomial can be factored as $(y+6)(y-3)$.
Thus, the completely factored form of the given polynomial is:
$=4y(y+6)(y-3)$