Answer
$(5x-2y)(3x-5y)$
Work Step by Step
$15x^{2}-31xy+10y^{2}$
... ... Searching for two factors of $ac=+150$ whose sum is $b=-31,$
we find$\qquad-6$ and $-25.$
Rewrite the middle term and factor in pairs:
$=15x^{2}-6xy-25xy+10y^{2}=$
$=3x(5x-2y)-5y(5x-2y)$
= $(5x-2y)(3x-5y)$
