Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 65



Work Step by Step

$15x^{2}-31xy+10y^{2}$ ... ... Searching for two factors of $ac=+150$ whose sum is $b=-31,$ we find$\qquad-6$ and $-25.$ Rewrite the middle term and factor in pairs: $=15x^{2}-6xy-25xy+10y^{2}=$ $=3x(5x-2y)-5y(5x-2y)$ = $(5x-2y)(3x-5y)$
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