## Intermediate Algebra for College Students (7th Edition)

$(5x-7y)(3x-2y)$
$15x^{2}+11xy-14y^{2}$ ... ... Searching for two factors of $ac=-210$ whose sum is $b=+11,$ we find$\qquad 21$ and $-10.$ Rewrite the middle term and factor in pairs: $=15x^{2}+21xy-10xy-14y^{2}=$ $=3x(5x-7y)-2y(5x-7y)$ = $(5x-7y)(3x-2y)$