Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 66



Work Step by Step

$15x^{2}+11xy-14y^{2}$ ... ... Searching for two factors of $ac=-210$ whose sum is $b=+11,$ we find$\qquad 21$ and $-10.$ Rewrite the middle term and factor in pairs: $=15x^{2}+21xy-10xy-14y^{2}=$ $=3x(5x-7y)-2y(5x-7y)$ = $(5x-7y)(3x-2y)$
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