Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 48

Answer

$(x-3)(5x-1)$

Work Step by Step

$5x^{2}-16x+3=$ ... ... Searching for two factors of $ac=+15$ whose sum is $b=-16,$ we find$\qquad-15$ and $-1.$ Rewrite the middle term and factor in pairs: $=5x^{2}-15x-x+3=$ $=5x(x-3)-(x-3)$ = $(x-3)(5x-1)$
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