# Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 63

$(2x+y)(3x-5y)$

#### Work Step by Step

$6x^{2}-7xy-5y^{2}$ ... Searching for two factors of $ac=6\cdot(-5)$ whose sum is $b=-7,$ we find$\qquad 3$ and $-10.$ Rewrite the middle term and factor in pairs: $=6x^{2}+3xy-10xy-5y^{2}=$ $=3x(2x+y)-5y(2x+y)$ = $(2x+y)(3x-5y)$

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