Answer
$3x^{2}(x-2)(5x-3)$
Work Step by Step
$ 15x^{4}-39x^{3}+18x^{2}\qquad$...factor out the common term, $3x^{2}$.
$=3x^{2}(5x^{2}-13x+6)$
Two factors of $ac=30$, whose sum is $b=-13$
are$ -10$ and $-3$.
Rewrite the middle term and factor in pairs.
$3x^{2}(5x^{2}-13x+6)$
$=3x^{2}(5x^{2}-10x-3x+6)$
$=3x^{2}[5x(x-2)-3(x-2)]$
=$3x^{2}(x-2)(5x-3)$
