Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 72



Work Step by Step

$ 15x^{4}-39x^{3}+18x^{2}\qquad$...factor out the common term, $3x^{2}$. $=3x^{2}(5x^{2}-13x+6)$ Two factors of $ac=30$, whose sum is $b=-13$ are$ -10$ and $-3$. Rewrite the middle term and factor in pairs. $3x^{2}(5x^{2}-13x+6)$ $=3x^{2}(5x^{2}-10x-3x+6)$ $=3x^{2}[5x(x-2)-3(x-2)]$ =$3x^{2}(x-2)(5x-3)$
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