Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 56



Work Step by Step

$4x^{2}-27x+18=$ ... ... Searching for two factors of $ac=+72$ whose sum is $b=-27,$ we find$\qquad-24$ and $-3.$ Rewrite the middle term and factor in pairs: $=4x^{2}-24x-3x+18=$ $=4x(x-6)-3(x-6)$ = $(x-6)(4x-3)$
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