Answer
$2x^{2}(4x-1)(3x+2)$
Work Step by Step
$ 24x^{4}+10x^{3}-4x^{2}\qquad$...factor out the common term, $2x^{2}$.
$=2x^{2}(12x^{2}+5x-2)$
Two factors of $ac=-24$, whose sum is $b=+5$
are$ -3$ and $8$.
Rewrite $5x$ as $-3x+8x$ and factor in pairs.
$24x^{4}+10x^{3}-4x^{2}$
$=2x^{2}(12x^{2}-3x+8x-2)$
$=2x^{2}[3x(4x-1)+2(4x-1)]$
=$2x^{2}(4x-1)(3x+2)$
