Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 71



Work Step by Step

$ 24x^{4}+10x^{3}-4x^{2}\qquad$...factor out the common term, $2x^{2}$. $=2x^{2}(12x^{2}+5x-2)$ Two factors of $ac=-24$, whose sum is $b=+5$ are$ -3$ and $8$. Rewrite $5x$ as $-3x+8x$ and factor in pairs. $24x^{4}+10x^{3}-4x^{2}$ $=2x^{2}(12x^{2}-3x+8x-2)$ $=2x^{2}[3x(4x-1)+2(4x-1)]$ =$2x^{2}(4x-1)(3x+2)$
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