Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 29



Work Step by Step

$(a+mb)(a+nb)=a^{2}+(m+n)ab+(mn)b^{2}$ $a^{2}-18ab+80b^{2}=$ Searching for two factors of $+80$ whose sum is $-18,$ we find$\qquad-10$ and $-8$ = $(a-10b)(a-8b)$
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