Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 67



Work Step by Step

$3a^{2}-ab-14b^{2}$ ... Searching for two factors of $ac=-42$ whose sum is $b=-1,$ we find$\qquad 6$ and $-7.$ Rewrite the middle term and factor in pairs: $=3a^{2}+6ab-7ab-14b^{2}=$ $=3a(a+2b)-7b(a+2b)$ = $(a+2b)(3a-7b)$
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