Answer
$(2x+3)(3x+5)$
Work Step by Step
$6x^{2}+19x+15=$
... ... Searching for two factors of $ac=+90$ whose sum is $b=+19,$
we find$\qquad+9$ and $+10.$
Rewrite the middle term and factor in pairs:
$=10x^{2}+9x+10x+6=$
$=3x(2x+3)+5(2x+3)$
= $(2x+3)(3x+5)$
