Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 26



Work Step by Step

$(x+my)(x+ny)=x^{2}+(m+n)xy+(mn)y^{2}$ $x^{2}-3xy-18y^{2}=$ Searching for two factors of $c=-18$ whose sum is $b=-3,$ we find$\qquad -6$ and $+3.$ $=(x-6y)(x+3y)$
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