Answer
$2y(2x-y)(3x-7y)$.
Work Step by Step
The given expression is
$=12x^2y-34xy^2+14y^3$
Factor out $2y$.
$=2y(6x^2-17xy+7y^2)$
Rewrite $-17xy$ as $-14xy-3xy$.
$=2y(6x^2-14xy-3xy+7y^2)$
Group terms.
$=2y[(6x^2-14xy)+(-3xy+7y^2)]$
Factor from each group.
$=2y[2x(3x-7y)-y(3x-7y)]$
Factor out $(3x-7)$.
$=2y(3x-7y)(2x-y)$
Rearrange.
$=2y(2x-y)(3x-7y)$.
