Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 78



Work Step by Step

$ 8a^{2}b+34ab-84b\qquad$...factor out the common term, $2b$. $=2b(4a^{2}+17a-42)$ ... Searching for two factors of $ac=-168$ whose sum is $b=17,$ we find$\qquad 24$ and $-7.$ Rewrite the middle term and factor in pairs: $=2b(4a^{2}+24a-7a-42)=$ $=2b[4a(a+6)-7(a+6)]$ = $2b(a+6)(4a-7)$
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