Answer
$2x^2(x-16)(x+3)$
Work Step by Step
All terms are divisible by $2x^2$, so factor out $2x^2$ to obtain:
$=2x^2(x^2-13x-48)$
Factor the trinomial. Look for factors of $-48$ whose sum is $-13$. These factors are $-16$ and $3$.
This means that the trinomial can be factored as $(x-16)(x+3)$.
Thus, the completely factored form of the given polynomial is:
$=2x^2(x-16)(x+3)$
