Intermediate Algebra for College Students (7th Edition)

$2x^2(x-16)(x+3)$
All terms are divisible by $2x^2$, so factor out $2x^2$ to obtain: $=2x^2(x^2-13x-48)$ Factor the trinomial. Look for factors of $-48$ whose sum is $-13$. These factors are $-16$ and $3$. This means that the trinomial can be factored as $(x-16)(x+3)$. Thus, the completely factored form of the given polynomial is: $=2x^2(x-16)(x+3)$