Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 53



Work Step by Step

$10x^{2}+19x+6=$ ... ... Searching for two factors of $ac=+60$ whose sum is $b=+19,$ we find$\qquad+15$ and $+4.$ Rewrite the middle term and factor in pairs: $=10x^{2}+15x+4x+6=$ $=5x(2x+3)+2(2x+3)$ = $(2x+3)(5x+2)$
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