Answer
$(2y-3)(8y+9)$
Work Step by Step
$16y^{2}-6y-27=$
... Searching for two factors of $ac=-16\cdot 27$ whose sum is $b=-6,$
we find$\qquad-8\times 3=24$ and $+9\times 2=+18.$
Rewrite the middle term and factor in pairs:
$=16y^{2}-24y+18y-27=$
$=8y(2y-3)+9(2y-3)$
= $(2y-3)(8y+9)$