Answer
$(y+2)(4y+1)$
Work Step by Step
$4y^{2}+9y+2=$
... ... Searching for two factors of $ac=+8$ whose sum is $b=+9,$
we find$\qquad+8$ and $+1.$
Rewrite the middle term and factor in pairs:
$=4y^{2}+8y+y+2=$
$=4y(y+2)+(y+2)$
= $(y+2)(4y+1)$
