Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 24

Answer

$(x-5y)(x-3y)$

Work Step by Step

$(x+my)(x+ny)=x^{2}+(m+n)xy+(mn)y^{2}$ $x^{2}-8xy+15y^{2}=$ Searching for two factors of $c=+15$ whose sum is $b=-8,$ we find$\qquad -5$ and $-3.$ $=(x-5y)(x-3y)$
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