#### Answer

False

#### Work Step by Step

$\dfrac{d}{dx}[\dfrac{\sin (x^2)}{x}+C] =\dfrac{2x^2 \cos x^2 -\sin x^2}{x^2}$
and $\dfrac{2x^2 \cos x^2 -\sin x^2}{x^2} \ne \dfrac{x \cos x^2 -\sin x^2}{x^2} $
Hence, the given statement is false.

Published by
Pearson

ISBN 10:
0-32187-896-5

ISBN 13:
978-0-32187-896-0

False

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