Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 65


a) False b) False c) True

Work Step by Step

a) $\dfrac{d}{dx}[\dfrac{(2x+1)^3}{3} +C]=\dfrac{1}{3}(3 (2x+1)^2)(2)\ne (2x+1)^2$; False b) $\dfrac{d}{dx}[(2x+1)^3 +C]=(3 (2x+1)^2)(2)\ne 3(2x+1)^2$; False b) Since,we have $\dfrac{d}{dx}[(2x+1)^3 +C]=(3 (2x+1)^2)(2) =6(2x+1)^2$; True
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