Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 11: 1

Answer

domain $(-\infty,\infty)$; range = $[1,\infty)$

Work Step by Step

Domain: $1+x^{2}$ is defined for all real numbers, so the domain is $(-\infty,\infty)$. Range: $x^{2}$ is always greater than or equal to 0, so $x^{2}+1\geq1$. This makes the range $[1,\infty)$
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