## Thomas' Calculus 13th Edition

Published by Pearson

# Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1: 1

#### Answer

domain $(-\infty,\infty)$; range = $[1,\infty)$

#### Work Step by Step

Domain: $1+x^{2}$ is defined for all real numbers, so the domain is $(-\infty,\infty)$. Range: $x^{2}$ is always greater than or equal to 0, so $x^{2}+1\geq1$. This makes the range $[1,\infty)$

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