Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 11: 10


$s=\frac{\sqrt 2}{2}d$ $a=\frac{1}{2}d^2$ $s$ - side $d$ - diagonal $a$ - area

Work Step by Step

We'll use s for side, d for diagonal and a for area. We know $s^2+s^2=d^2$, which makes $s^2=\frac{d^2}{2}$ Since $s^2=\frac{d^2}{2}$ and $s^2=a$, we can conclude that $a=\frac{d^2}{2}$
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