Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 60

Answer

$\csc^2 (\dfrac{x-1}{3})$

Work Step by Step

Need to solve. $\dfrac{d(-3 \cot(\dfrac{x-1}{3})+C)}{dx}=(3)[\dfrac{1}{3 \sin^2 (\dfrac{x-1}{3})}]$ or, $=\csc^2 (\dfrac{x-1}{3})$
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