Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 52

$\theta+\tan \theta +C$

Integrate. $\int 2 d\theta + \int (\tan^2 \theta )d\theta$ Thus, we have $\int 2 d\theta + \int (\tan^2 \theta )d\theta= 2 \theta + \int (\sec^2 \theta )d\theta -\int 1 d\theta$ or, $=\theta+\tan \theta +C$