Answer
$4 \sec x -2 \tan x+C$
Work Step by Step
As we are given that $ 4 \int (\sec x \tan x ) dx - 2 \int (\sec^2 x) dx$
Thus, we have $4 \int (\sec x \tan x ) dx - 2 \int (\sec^2 x) dx=4 \sec x -2 \tan x+C$
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