Answer
$4 \sec x -2 \tan x+C$
Work Step by Step
As we are given that $ 4 \int (\sec x \tan x ) dx - 2 \int (\sec^2 x) dx$
Thus, we have $4 \int (\sec x \tan x ) dx - 2 \int (\sec^2 x) dx=4 \sec x -2 \tan x+C$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 4: Applications of Derivatives - Section 4.7 - Antiderivatives - Exercises 4.7 - Page 239: 43
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